OPGAVEN
1. Los algebraïsch op:   5 • 2x + 1 - 15 = 0
2. Los algebraïsch op:   4 • 3log x - 8 = 0
3. Los algebraïsch op:   2 • 3log x = 3log (x - 2) + 2
4. Gegeven  is, dat   p = 6 • 2q . Daaruit volgt dat  q = a + 2 log p .  Bereken algebraïsch a.

OPLOSSING
1. 5 • 2x + 1 - 15 = 0   Þ  2x + 1 = 3  Þ   x + 1 = 2log 3 Þ  x =  2 log 3 - 1 (» 1,58)
2. 4 • 3log x - 8 = 0 Þ 3 log x = 2   Þ  x = 32 = 9
3. 2 • 3log x = 3log (x - 2) + 2
Þ  3log x2 = 3log(x - 2) + 3log 9
Þ  3log x2 = 3log((x - 2)•9)
Þ  x2 = 9(x - 2) = 9x- 18
Þ  x2 - 9x + 18 = 0
Þ  (x - 6)(x- 3) = 0
Þ  x = 6  V   x = 3
4.   p = 6 • 2q  
Þ  1/6p = 2q 
Þ  q = 2 log(1/6p) = 2 log p + 2 log1/6
dus a = 2 log(1/6) = log(1/6)/log(2) » -2,58